3(2(x-3)+2)+5(x-3)

## 3(2(x-3)+2)+5(x-3)

# 3 Answers

My favorite math teacher often shouted "GEMAL says......!" What he means by that is to remember what this acronym means:

- Grouping
- Exponents
- Multiplication & Division
- Addition & Subtraction
- Left to Right

So, when performing the calculation remember to

- respect the parenthesis working from the inside out
- Solve the exponents if there are any, like changing 2
^{3 }to 8 for example. - Do multiplication/division before addition/subtraction
- Finally, do addition and subtraction last
- Within a given pair of parenthesis, do the above from left to right.

This explanation doesn't account for variable X but I thought to still share this as it has served me well over the years.

**Separate the 2 parts** of the problem: 3(2(x-3)+2) and
5(x-3)

Starting with 3(2(x-3)+2), **distribute** the first 2 to x-3:

2(x-3) = 2x-6

Now you have: **3(2x-6+2)**

**Add** 2 to -6: 3(2x-4)

**Distribute** the 3: 6x-12

Now you can work on the other part of the problem, 5(x-3).

**Distribute** the 5 to x-3: 5x-15

Put the **2 pieces back together**: 6x-12+5x-15

**Simplify** it to get the **answer**: **11x-27**

Always work with the parenthesis first: so

work with the (2(x-3)+2)first and then the 5(x-3)

then work out the like variables (2x-6+2) then, use the distributive property on 3(2x-4). Then, work through all the like variables for your final answer.

3(2(x-3)+2)+5(x-3)

3(2x-6+2)+(5x-15)

3(2x-4)+(5x-15)

6x-12+5x-15

=11x-27