Find the value of c that makes each trinomial a perfect square. Then write the trinomial as a perfect square.

## x^2+11x +c

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# 1 Answer

A trinomial that was a perfect square (with a leading coefficient of 1) is formed by multiplying (x + a)(x + a) to get x^{2} + 2ax + a^{2}. Looking at the linear coefficient of our original equation, 2a = 11, so a = 11/2. We then square this
to get a^{2} = (11/2)^{2} = 121/4^{
}

So our new trinomial is **x ^{2} + 11x + 121/4**