complete the square using the square root property

## x^2-2x+1=2

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# 1 Answer

using the quadratic formula to find the roots (solutions) of any equation of the form: ax^{2
}+ bx + c = 0

x = (-b±√(b^{2 }- 4ac))/2a

applied to our equation x^{2 }- 2x + 1 = 2 after we make the right side equals 0 it becomes x^{2} - 2x - 1 = 0

so from it we can read that a=1, b=-2, c=-1

pluging these values for a,b and c in the quadratic formula above to find the x values we have

x =( -(-2)±√( (-2)^{2 }-4(1)(-1) ) )/2*1 = ( 2 ± √8 )/2 = ( 2 ± √(2*4) )/2 = ( 2 ± √4 * √2)/2 = ( 2 ± 2√2)/2 = 2/2 ± 2√2/2 = 1 ± √2

So x values are x= 1 + √2 and x= 1 - √2