complete the square using the square root property

## x^2-6x+9=5

# 1 Answer

here is how you proceed to complete the square on this equation (means to make the expression that involve x a complete square. also means to know how much you need to add to BOTH sides of the equation to make it a complete square if it is NOT ALREADY a complete square)

first look for x (not x^{2 }) and read its coefficient (means the number that is multipled by x) which is
**-6**

second take half this number -6/2 which is **-3**

third square the result (-3)^{2 }which is **9**

Now you can see that there is already **9** on the right side of the given equation, so there is no need to add
**9 **to BOTH sides! and that means the right side is already a complete square and so we can write it like follows:

** (x-3) ^{2
}= 5 **

(note that x is the square root of x^{2 }and - sign is the sign of the term that invole x and 3 is the square root of 9 - the number that make the right side a complete square)