i cnt figure out how to do this
(2,-2) slope=2 how to put it in slope intercept form
The equation of a line is
y-y1=m(x-x1) ,where y1 is your y-cord, m is your slope and x1 is your x-cord.
the information you provided was m=2, (2,-2)
now plug in
now solve for y to put it in the form of y=mx+b where m is your slope and b is your y intercept
The equation of a line is given by:
y = mx + b
where m = slope = 2 and therefore y = 2x + b. Since x = 2 and y = -2 (this is given by the point at (2,-2)), you can solve for b:
-2 = 2(2) + b
-2 = 4 + b
-6 = b
Thus the equation of the line that passes through the point (2, -2) and has slope = 2 is
y = 2x - 6
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I can help yuo...
two ways to answers this.
Y=mx plussign b
(2,-2) M=2 Substitude and Point intersept and slope
slove for b?
-2=2(2)plus sign b
-2=4plus sign b