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x(x+1)(x+2)

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4 Answers

x(x+1)(x+2)

 simply multiply the first bracket with x and then with the total multiply it with the second bracket

x2+x(x+2)

cross multiply:

x3+2x2+x2+2x

x3+3x2+2x

Go for a longer but the simplest method: x(x+1)(x+2)

x(x+1)=(x2+x)

(x2+x)(x+2)=x3+3x2+2x

Not sure if this is a question on finding the roots, if it is:

You look to see what x values can make the whole expression zero. Well all those three quantities (the three sets of parenthesis), are all multiplying together.

x * (x+1) * (x+2). Well the only ways to make something times something equal zero is what... think about that for a second before you read...

 

if one of the something's themselves is zero (8 * 0 = 0 for example). 

With that in mind, what makes the first quantity (x) equal zero? What value makes the second quantity (x+1), equal zero? and the third quantity? Those will be your three options to making the expression as a whole equal zero.

x (x+1) (x+2)=

First distribute the x:

(x2+x) (x+2)= 

Then use the foil method:

(x2*x + x2*2 + x*x + x*2)=

Finally collect the terms and you have:

(x3+3x2+2x)