I need help/:
Solve for A: 1/4 ( 3a - 2q ) = k
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1 Answer
1/4(3a-2q)=k
(3a-2q)/4=k
3a-2q=4k
3a=4k+2q
a=(4k+2q)/3
I need help/:
1/4(3a-2q)=k
(3a-2q)/4=k
3a-2q=4k
3a=4k+2q
a=(4k+2q)/3