divide using dividion algorithm. write answer in form Q+ R/D where the degree of R< the degree of D

## (2x^2-9x-20)/(2x+3)

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# 1 Answer

` x - 6`

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2x+3 ) 2x^{2} - 9x - 20

-(2x^{2} + 3x)

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-12x - 20

-(-12x - 18)

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- 2

The solution is x - 6 - 2/(2x+3).

## Comments

I wanted to put the answer in a formatted way first. Now I'll talk about how I did this problem.

First, I started by looking at 2x

^{2}. If I divide this first term by 2x, what do I get? That answer is x. So when I multiply x by 2x+3, I get the quantity 2x^{2}+ 3x. Just like in long division, you subtract this product out, leaving -12x - 20. -12x goes into 2x -6 times. Multiply 2x+3 by -6 gives you -12x - 18, which you subtract out leaving -2. You can't go any further so the remainder is written in fractional form with the divisor as the denominator: -2/(2x+3). So you final answer is x - 6 - 2/(2x+3). This satisfies the question, as R has x to the 0th power and D has x to the 1st power, and has been expressed as Q + R/D... quotient plus remainder over divisor.And I apologize for the grammatical errors. I can't edit my comment to go back and fix them, only the original posting. I hope this helps you.

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