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# whats the square root of 49x and x has a exponent of 6

its just dificult

### as power of a factor to even number, i,e.  √X 2n  , or odd number as  √X2n+1 .

Juniper...let me add a small element you should know, when it comes to solving problems with a coefficient and a variable(I'm assuming you know what these terms are...). Rule/Skill 1: when solving the power of an expression(finding the square...cubed...root...etc) of an expression...separate the expression into the constants(values you know) and the variables(values you don't know), in your case. /49x^6 basically the square root of the expression 49 x to the 6th power. This is the same as 49 times x to the 6th power and can be written like this /(49) x /(x^6) in this case...I'm using / to represent square root. I'm sure you already know, the square root of 49 is /49 = 7, that's for the knowns. Now, for the unknowns /x^6 which in words is the square root of x to the 6th power. So (some value x) times (some value x) equals x^6. As it turns out, as explained above (x^3) times (x^3) equals x^6 or (x^3)(x^3) = x^6. Finally; /49x^6 = 7x^3 Hope that helps...good luck