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## For the equation 21x-2y=1 indicate the slope, x-int, y-int

Quadratic form back to Slope intercept form

The slope-intercept form is : y = mx + b

To change to slope intercept form you do the followings: 1) subtract 21x from both sdes

21x - 2y = 1

- 21x + 21x - 2y = 1 - 21x >>> - 2y = -21x +1

2) divide both sides by -2

-2y/-2 = -21x/-2 + 1/-2 >>> y = 21/2x - 1/2

Slope-intercept form: y = (21/2)x - 1/2

y = mx + b

m = slope = 21/2

Y-int : let x = 0

y = 21/2 (0) - 1/2  = -1/2 = b

X-int: let x = 0 ( you can use the slope intercept

form but it's easier to use the original equation)

21x - 2(0) = 1 >>> 21x= 1 Now solve for x by

dividing both sides by 21

21x/21 = 1/21 >>> x = 1/21

Hope this helps. Good luck!!

Hey there :), so for x-intercept form what you do is you assume that the other variable in this case(y) is 0, 21x-2(0)=1 , therefore it cancels out so you are left with 21x=1 so you solve and get x=1/21 . Now for y-int. form you to the same but now x is zero, 21(0)-2y=1 , now you are left with -2y=1 and you divide and get y=-1/2 . So basically what u do is cancel or just ignore the other form that you are not looking for.  I hope this helped :) Let me know if you have questions :).