I'm not sure how to answer this problem so any help on how to solve this problem would be appreciated. Thanks!
Find two numbers such that 6 times the first added to 5 times the second equals -9, and 5 times the first added to 8 times the second equals 4.
Let x = 1st number
Let y = 2nd number
Read the problem and translate into two sets of simultaneous equations, and solve by elimination:
6x + 5y = -9 multiply every term of this equation by 5
5x + 8y = 4 multiply every term of this equation by -6
You now have the following equivalent equations where you can eliminate the terms containing x and solve for y.
30x + 25y = -45
-30x - 48y = -24
0x -23y = -69 (divide both sides by -23)
y = 3 plug in 3 for y in either equation and you will find that x = -4
x = -4
Reread the problem and make sure your two solutions make sense...
Sometime the equations will become apparent by reciting the question a little differently:
6 times (the first number) added to 5 times (the second number) equal -9
Now let the first number be x and the second be y and use some mathematical symbols:
6x + 5y = -9
Do the same for the next part of the sentence and you will have two simultaneous equations. These can be solved by substitution.