two boats leave the harbor at 9:00 am. Boat A sails north at 20 km/hr. Boat B sails west at 15km/hr. 158, How far apart are the two boats at noon? helpppp

## two boats leave the harbor at 9:00 am. Boat A sails north at 20 km/hr. Boat B sails west at 15km/hr. 158, How far apart are the two boats at noon?

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# 2 Answers

North bound : 20km x 3 hours = 60 KM. west bound 15km x 3 hours = 45 km. Now 60^2 + 45^2 = 3,600+ 2025 = 5625. Square root of 5,625 =75. they are 75 km apart. (using the Pythagorean theorem)

Be sure to apply the Pythagorean formula: the length of the hippopotamus (hypotenuse) squared is equal to the sum of the squares of the lengths of the legs.

c= √(a^{2} + b^{2})

# Comments

That's what I did thank you!

You're welcome.

## Comments

is it 105km?

Not quite. Did you get a distance of 60 km traveled by boat A and 45 km traveled by boat b? And did you then apply the Pathagorean formula (a

^{2}+ b^{2}= c^{2})?I get the distance right for both and then I added them that's how I got 105, but if I do the Pythagorean formula I get 75 km apart, is this the right answer?

Yes! Very good!

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