I get confused on how to do the signs

## how do i put 6-7y+4x/3=1 in slope-intercept form

# 2 Answers

You want to isolate y on one side, and the rest on the other.

Start by adding 7y to both sides to get **6 + 4x/3 = 1 + 7y**

Then subtract 1 from both sides to get **4x/3 + 5 = 7**

Now, divide both sides by 7. **(4x/3)/(7) + (5)/(7) = y**

Simplifying, we get **4x/21 + 5/7 = y**

Wait... doesn't y belong on the left? We usually see it that way, but the Symmetric Property of Equality says that if **a = b then b = a**. Therefore, we can rewrite the equation as **y = 4x/21 + 5/7**

The slope-intercept form is y=mx+b, so you have to solve given equation for y.

6 - 7y + 4x/3 = 1

-6 -6

- 7y + 4x/3 = -5

- 4x/3 - 4x/3

- 7y = -4x/3 - 5

-7y/(-7) = (-4x/3)/(-7) -5/(-7)

y = (4/21)x + 5/7

4/21 is a slope, and (0 , 5/7) is coordinates of y-intercept

## Comments

Thank you Kevin :-)

Comment