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how do you graph 5x+6y=225 and x+y+40

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When graphing linear equations, the easiest way is to put it into slope-intercept form: y=mx+b (m being the slope, and b being the y-intercept).

So, to put the first equation into slope-intercept form, we subtract the 5x from both sides of the equation, resulting in 6y = -5x + 225. Then we divide both sides by 6, resulting in our slope-intercept form: y= -5x/6 + 75/2. Using the slope-intercept method of graphing, we put our b (75/2) on the y-axis, count 5 units down and 6 units across (-5 rise / 6 run), and then draw a straight line through the two points.

For the second one (x+y+40=0), we isolate y by subtracting x and 40 from both sides, resulting in the slope-intercept form: y= -x - 40. Using the slope-intercept method of graphing, we put our b (-40) on the y-axis, count 1 unit down and 1 unit across (-1 rise / 1 run), and then draw a line through both points.

I hope that gives you an idea of how to solve other similar problems.