Write the standard form of the conic equation in which Eccentricity = sqr(11)/4 Vertices: (0, 9+4(sqr 5)), (0, 9-4(sqr(5)) I have the answer of x^2 /25 + (y-9)^2 /80 = 1 but I don't understand how to get it. Thank you so much. Aug 28 | Austin from Alpharetta, GA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
Eccentricity= c/a=sqrt(11)/4 As per given vertices,major axis is vertical. 9+4sqrt(5)-9+4sqrt(5)=8sqrt(5)=2a So, a=4sqrt(5) c/a=sqrt(11)/4. =c/4sqrt(5) c=sqrt(55) c^2= a^2. -b^2 55=80-b^2 b=5 Center coordinates= (0,9) Equation of ellipse is [(x^2)/25] + [(y-9)^2]/80=1 YOU are welcome to revert back if any step is not clear. Aug 28 | SURENDRA K. Best answer Comment