Reviewing for a algebra one exam!
what is y= 1/2 + 3 written in standard form using integers
I'm sure you meant y = 1/2 x + 3
If that's the case then you would follow these steps.
First you will need to eliminate the fraction by multipling everything by 2.
2(y) = (1/2)(2)(x) + 3(2) which in turn equals
2y = x + 6
Now we need to put both the x and y on the same side by subtracting x from both sides
2y - x = x - x + 6 which equals
2y - x = 6
Standard Form is Ax + By = C so rearrange the problem to
-x + 2y = 6
The Standart for is: Ax+By = C
y= 1/2 + 3, I thing that you missing some variable that could be called "x" or "z"
you expression could be writen y=x/2+3 or y= 1/2 +3x or y=x/2 + 3z, I do not know.
To solve it
step 1: re write the equation eliminating the fraction form, to do this mult it by 2
for y=x/2 + 3 ==> 2y=x+6 ==> 2y-x = 6 ==> x-2y=-6
for y= 1/2 +3x ==> 2y=1+6x ==> 6x-2y=-1 or 2(3x-x)=-1
for y=x/2 + 3z ===> 2y=x+6z ==> x-2y+6z=0, where the standar form is Ax+By+Cz=D