A 50-kg ice skater spins about a vertical axis through her body with outstretched arms. She makes 2 turns each second. The distance from one hand to the other is 1.60 m. Each hand makes up approximately 1.25% of the body weight
a) What horizontal force does her wrist exert on the hand?
b)If she spins faster (3 turns each second), what is the percentage change of the force on the hand?
from what I have, I think the force of wrist exerted on hand is = 78.75 N
for part B, I changed the denominator in the acceleration formula to seconds for each of the three turns rather than two, plugged it in to the force equation, and got 287 N. An increase of 265%. Is this correct? Thanks!