hello i need help to solve 4^x=3^x+1 i can't find out how to do it i know that i have to use LOG but how??? could you help me step by step?? Jakob

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# 1 Answer

4^x=3^(x+1) <==Is this what you want to solve?

Take ln,

xln4 = (x+1)ln3, using the log property lna^b = blna

Solve for x,

x = ln3/(ln4 - ln3) <==Answer