absolute value of X+6=2x-3 what is the extraneous solution?
Absolute value of x is always positive.
So |x|+6=2x-3 means
x+6=2x-3 only if x is positive or -(x)+6=2x-3 only if x is negative
x+6-x=2x-3-x or -x+6+x=2x-3+x
6=x-3 or 6=3x-3
6+3=x-3+3 or 6+3=3x-3+3
x=9 or 3x=9 i.e. 3x/3 = 9/3
x=9, here x is positive or x=3, here x is not negative.
So this is an extraneous solution
Check the answer
|9|+6=2x9-3 or |3|+6=2x3-3
15=15. correct answer or 9=3 extraneous (incorrect) answer
I assumed that absolute value of x+6=|x|+6.
If by "absolute value of x+6", you mean |(x+6)|, then you can get extraneous solution by solving
-(x+6)=2x-3 only if (x+6) < 0