(m/4 n/3) ^{-1}

_________________

(-5m /-3 n4)^{2}

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(m/4 n/3) ^{-1}

_________________

(-5m /-3 n4)^{2}

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Assuming the original problem is: [(m/4)*(n/3)]-1 divided by [(-5m/-3)*(n^{4})]^{2}

The numerator becomes (mn/12)^{-1.} Any fraction to the -1 power is just flipped, so this becomes 12/mn

The denominator becomes (-5mn^{4}/-3)^{2 } Squaring a fraction means squaring its numerator and denominator, so this becomes 25m^{2}n^{8}/9.

Put them together you get (12/mn)/(25m^{2}n^{8}/9) = (12/mn) * (9/25m^{2}n^{8})

Multiply across: = **108/25m ^{3}n^{9}**

Assuming the original problem is: [(m/4)*(n/3)]^{-1} divided by [(-5m/-3)*(n^{4})]^{2}

= 1 divided by [(mn/12)] [(5mn^{4}/-3)^{2}]

= 1 divided by (mn/12) (25m^{2}n^{8}/9) = 1 / (25m^{3}n^{9}/108) =
**108 / 25m**^{3}**n**^{9}

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## Comments

Is the denominator (-5m/-3 * n

^{4})^{2}or is it (-5m/-3n

^{4})^{2}or something else?

Comment