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Find all real number solutions for 4y^2-25=0

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1 Answer

Method I.

Factor out,

(2y+5)(2y-5) = 0

2y+5 = 0 => y = -5/2

2y-5 = 0 => y = 5/2

 

Method II.

Isolate y^2,

y^2 = 25/4

Take square roots on both sides,

y = +/- 5/2