Although James has correctly identified one possible answer, this question is in fact ill-posed as the next three terms in the sequence could be any three values. I'll demonstrate by making the next three terms N_{1 ,
}N_{2 }and N_{3. }Then the sequence could be generated as the solutions to this algebraic equation:
(x - 2)(x - 5)(x - 10)(x - 50)(x - N_{1})(x - N_{2})(x - N_{3}) = 0 where N_{1} , N_{2} and N_{3} are any numbers.