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quadratic formula #10

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If this is the question:  5X2+2X-3=0 then the answer is simple:
 
quadratic formula is that for an equation with the form aX2+bX+c=0 then X=(-b+/- sqroot(b2-4.a.c))/2.a
 
so the answer would be  X=(-2+/- sqroot(4-4(5)(-3)))/10
 
4-4(5)(-3)=64 and sqroot(64) = 8 then...
 
X= (-2+/-8)/10 you'll have 2 solutions:
 
X1 = (-2+8)/10 = 6/10 = 3/5
 
X2 = (-2 - 8)/10 = -10/10 = -1
 

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