If this is the question: 5X^{2}+2X-3=0 then the answer is simple:
quadratic formula is that for an equation with the form aX^{2}+bX+c=0 then X=(-b+/- sqroot(b^{2}-4.a.c))/2.a
so the answer would be X=(-2+/- sqroot(4-4(5)(-3)))/10
4-4(5)(-3)=64 and sqroot(64) = 8 then...
X= (-2+/-8)/10 you'll have 2 solutions:
X1 = (-2+8)/10 = 6/10 = 3/5
X2 = (-2 - 8)/10 = -10/10 = -1