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Helppppp Please ( solving system of equations)

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2 Answers

3x+4y=9
4x-37=-13
 
OK, you did write the equations down incorrectly.  They should be:
 
3x+4y = 9
4x-3y = -13
 
Let's re-write them in standard form y = mx+b
 
3x+4y = 9
4y = 9 - 3x
y = (9/4) - (3/4)x
 
4x-3y=-13
-3y = -13 - 4x
y = (13/3) + (4/3)x
 
Now set the two equations equal.  This is the point where the two lines intersect:
 
(9/4) - (3/4)x = (13/3) + (4/3)x
(9/4) - (13/3) = (4/3)x + (3/4)x
-25/12 = (25/12)x
 
-1 = x
 
Solve for y by plugging x = -1 into either original equation:
 
3x + 4y = 9
3(-1) + 4y = 9
-3 + 4y = 9
4y = 12
 
y = 3
 
Answer is (-1,3)
 

Comments

see the answers could only be 
 
A. (-1,-3)
B. no solution 
C. infinitely many solutions
D. (-1,3)
Oops, I plugged in x=3 instead of x=6, so the y value is -9/4 vice 0. 
 
Since (6,-9/4) is not one of the options, did you write the equations down correctly?
You did write the equations down incorrectly - the second equation should be 4x-3y=-13 vice 4x-37=-13. I've corrected the answer above.
LOL! You are more patient than I am. I noticed that, and decided to step away from this problem. Lots of time wasted.
You were probably the wiser one of the two of us.  That second equation - without a y term - was suspect.  But once I made the mistake of stepping in, I needed to try to figure it out.  ;-)
Bravo! I admire your dedication.