The question is x^3 y^3 + 27. Jun 6 | Melanie from Bronx, NY | 2 Answers | 0 Votes Mark favorite Subscribe Comment
Hi Melanie, x^3y^3+27 =(xy+3)(x^2y^2-3xy+9).......................................using x^3+y^3=(x+y)(x^2-xy+y^2) Meena Jun 6 | Meena S. Comment
This is in the form a^{3} + b^{3}, where a is xy and b is 3. The factoring formula is a^{3} + b^{3} = (a + b)*(a^{2} - ab + b^{2}). x^{3}y^{3 }+27 = (xy)^{3 }+ 3^{3 }= (xy + 3)(x^{2}y^{2 }- 3xy + 9) Jun 6 | Alex S. Comment