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a plane is passed through a sphere at a point that is x units away from the center of a sphere. the radius of the sphere is y units.

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1 Answer

Hi Jennie,
 
When a plane passes through a sphere, the resultant cross section formed is a circle. If you try to think over it, you can easily deduce the radius of that circle as Square-root(y^2-x^2) ( Try thinking it as a right triangle with hypotenuse y unit and the other two sides as x and the radius of the cross-sectional circle)
 
 
Therefore the cross-sectional area will be π*(y^2-x^2) as area of a circle with radius r is π*r^2