I just need help. If someone could give me the answer as well as explain it, that would be amazing

If z is a complex number, written in polar form as

z=8(cos(4pi/5) + isin(4pi/5)

then z^(1/3) = (8(cos(4pi/5) + isin(4pi/5))^(1/3)

= 8^(1/3)(cos((1/3)(4pi/5+2pi*k)) + isin((1/3)(4pi/5+2pi*k))) where k=0,1,2

when K = 0, arg z= 4pi/15 the root a

_{0}= 2(cos(4pi/15)+isin(4pi/15)) = 1.33826 + 1.48629i k = 1, arg z= 14pi/15 a

_{1 = 2(cos(14pi/15)+isin(14pi/15)) = -1.95623 + 0.41582i} k = 2, arg z= 24pi/15 a

_{2 = 2(cos(24pi/15)+isin(24pi/15)) = 0.61803 - 1.90211i}