Write the equation in slope-interest form and identify the slope and the 7 intercept. 2x-5y+10=0
Can you help me with this:
I think you meant slope- intercept form.
The equation of a line is y=mx+b
y= how far up
x= how far along
m= slope (steepness of the line)
b= y intercept (where the line crosses the y axis)
To get the equation in slope intercept form
First, we need to move 5y to the right side of the equation so that the y variable is isolated.
2x +5y-5y+10= -5y
Leaves 2x+10= -5y
Then we need to flip the equation around to read
To solve for y we use the inverse operation of division. we will divide -5y by -5. Remember, you have to perform the same operation for all terms on both sides of the equations.
Therefore: -5y/-5= 2x/-5 + 10/-5 = y = 2/-5 x -2
The slop-intercept form of this equation will be y= 2/-5 x - 2
The slope will be -2/5
The y-intercept will be -2
I think you meant slope-intercept form.
To solve for slope-intercept form of a linear equation, solve the equation for y.
2x - 5y + 10 = 0 Given
2x - 5y + 10 - 2x - 10 = 0 - 2x - 10 Subtract 2x and 10 from each side
- 5y = - 2x - 10 Simplify
-5y/(-5) = (-2x - 10)/(-5) Divide each side by -5
y = (2/5)x + 2 Simplify each side (distribute the -5 on right side)
The slope-intercept form of the equation is y = (2/5)x + 2.
The slope is the fraction that is multiplied by x (2/5).
The y-intercept is the constant being added to the slope times x (+2).