How do I prove that sin^2 x(1 + cot^2 x) = 1 thanks May 16 | L from Jacksonville, NC | 1 Answer | 0 Votes Mark favorite Subscribe Comment
sin^{2}(x)[1 + cot^{2}(x)] = 1 Identity: cot(x) = cos(x)/sin(x) sin^{2}(x)[1 + cos^{2}(x)/sin^{2}(x)] = 1 Distribute the sin^{2}(x) across the terms in the brackets: sin^{2}(x) + cos^{2}(x) = 1 which is a Pythagorean Identity. May 16 | Philip P. Comment