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Sin^2 x question

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1 Answer

sin2(x)[1 + cot2(x)] = 1
 
Identity: cot(x) = cos(x)/sin(x)
 
sin2(x)[1 + cos2(x)/sin2(x)] = 1
 
Distribute the sin2(x) across the terms in the brackets:
 
sin2(x) + cos2(x) = 1
 
which is a Pythagorean Identity.