solve the initial value theorem. dy/dt=1/t, y(-1)=9 May 11 | Allison from San Diego, CA | 0 Answers | 0 Votes Mark favorite Subscribe Comment Comments hi Allison, Are you sure the problems stated correctly? The general solution to dy/dt=1/t is y= ln(t)+c. But the log of a negative number is imaginary (pi*i) so y(-1) implies c=9-pi*i Is that wahta you were looking for? Jim May 11 | Jim S. Comment
hi Allison, Are you sure the problems stated correctly? The general solution to dy/dt=1/t is y= ln(t)+c. But the log of a negative number is imaginary (pi*i) so y(-1) implies c=9-pi*i Is that wahta you were looking for? Jim May 11 | Jim S.
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