14y^3+8y^2+7y+4 May 11 | Nick from Jefferson City, MO | 1 Answer | 0 Votes Mark favorite Subscribe Comment
Try factor by grouping 14 Y^3 + 7Y + 8Y^2 +4 7Y (2Y^2 +1) + 4 ( 2Y^2 +1) You found the GCF . now continue. May 11 | Parviz F. Comment