Search 72,430 tutors FIND TUTORS
Search for tutors
Ask a question
0 0

Can you help me with a question?

Tutors, please sign in to answer this question.

1 Answer

Ok, so knowing where to start is the main point:  Do parentheses and exponents first - let's take the top half (numerator):

Let's re-write the top (numerator) 3a(b-4) as (3a)(b-4)(b-4)  - this simply shows that (b-4)2 = (b-4)(b-4), just like (2)(2) = 22

The bottom (denominator) is 3a(b-4), can also be written as (3a)(b-4)

 

 

Now we have [(3a)(b-4)(b-4)] / [(3a)(b-4)].   (3a) / (3a) = 1, and (b-4) / (b-4) also = 1, so we're left with only one of the original (b-4) terms, and the answer is b-4