I need help with factoring this expression.

## factor x^2+2x+48

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# 2 Answers

X^2 + 2X + 48 =

X^2 + 2X + 1 = -47

( X + 1 ) ^2 +47 =

( X +1 + i √47) ( X +1 - i√47)

x

^{2}+ 2x + 48As written, the equation does not factor. In fact, using the quadratic formula, it has complex roots:

x = -1 ± i√47

If the equation is really x

^{2}- 2x - 48, the factors are (x+6)(x-8)If it's really x

^{2}+ 2x - 48, the factors are (x-6)(x+8)
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