2log_{4}(2x-3)=4
please solve
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2 Answers
Another approach: 2log_{4}(2x-3)=4. Divide by 2: log_{4}(2x-3)=2.
Write in exponential form: log_{4}(2x-3)=2 becomes 4^{2}=2x-3.
solve: 2x-3=16.
Kevin
2log_{4}(2x-3)=4
log_{4}(2x-3) = 2 [Divided both sides by 2]
4^{log4(2x-3)} = 4^{2} [Raised everything as exponents to 4]
2x-3 = 16 [ 4^{log4a} = a, 4^{2}=16]
Solve for x