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N^2+n/2=465

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2 Answers

We have a quadratic equation of the form  n^2+n/2-465=0. the solution of the quadratic is x=(-b±√(b^2-4*a*c))/2*a. the values will be a= 1; b= 1/2; c= -465. plugging this values we reach:
n= (-1/2±43.13)/2.
solve for n1 with plus sign and for n2 with the minus sign.
 
 
N^2 + n/2 + 465
 
2N^2 + N - 930= 0
 
 N = -1/4 ±√(1+7440)/4
 
      = -1/4 ±86.26/4 = 
 
       = - 21. 82, 21.31