integrate from pi/6 to pi/2 (x+16/(sinx^2))dx Apr 25 | Allison from San Diego, CA | 0 Answers | 0 Votes Mark favorite Subscribe Comment Comments Sup bro I dont know if u noe this already but 1/sin^2(x) = csc^2(x) So, Apr 25 | Brian from Dulles, VA If you use the indefinite intergral of everything, you should get ((x^2)/2) - 16cot(x) + C ............. since integration of csc^2(x) is - cot(x) + C but since we are doing definite, you just use the normal process of doing definite integration. i.e. substitute pi/2 on that and then subtract it by pi/6. your exact final answer should be (16√3) + (pi^2)/9 Apr 25 | Brian from Dulles, VA Comment
Sup bro I dont know if u noe this already but 1/sin^2(x) = csc^2(x) So, Apr 25 | Brian from Dulles, VA
If you use the indefinite intergral of everything, you should get ((x^2)/2) - 16cot(x) + C ............. since integration of csc^2(x) is - cot(x) + C but since we are doing definite, you just use the normal process of doing definite integration. i.e. substitute pi/2 on that and then subtract it by pi/6. your exact final answer should be (16√3) + (pi^2)/9 Apr 25 | Brian from Dulles, VA
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