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3x^2+14x-5=0 solve quadratic fomula

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2 Answers

{(-14) + √[(142)-(4)(3)(-5)]}/(2*3)= 2/6 = 1/3
 
1. square 14 = 196
2. multiply 4, 3, and -5 to get -60
3. subtract -60 from 196 = 196--60= 196+60= 256
4. take the square root of 256 = √256= 16
5. add 16 to -14 = 16 - 14=2
6. multiply 2 by 3 = 2*3 = 6
7. Divide 2 by 6 = 2/6 = 1/3
AND
{(-14) - √[(142)-(4)(3)(-5)]}/(2*3)= -30/6 = -5
1. square 14 = 196
2. multiply 4, 3, and -5 to get -60
3. subtract -60 from 196 = 196--60= 196+60= 256
4. take the square root of 256 = √256= 16
5. subtract 16 from -14 = -14 -16=-30
6. multiply 2 by 3 = 2*3 = 6
7. Divide -30 by 6 = -30/6 = -5

Comments

If you would like me to break it down into more steps I can.  Please let me know.
 
This is a very ugly one. Because the quadratic equation is not nice at all.
So try factoring, by first pulling out the leading 3:
3( x2 + 14x3  - 53 ) ⇒ 3(x + 5 )( x - 1/3)   Not easy to arrive at, unfortunately

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