how do I write in logarithmic form using (1/2)^4 - 1/16 I have log 16 = 2 thanks Apr 22 | L from Jacksonville, NC | 1 Answer | 0 Votes Mark favorite Subscribe Comment
Are you sure of the problem? As this is written, log 16 = 2, means that the log base is 10, and 10^2 = 16. I think this may be log_{b}16 = 2, or b^{2} = 16. Is this correct? Apr 22 | Kevin C. Comment Comments I was wrong. It is written as (1/2)^4 = 1/16 Apr 24 | L from Jacksonville, NC Comment
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