Find the volume of the solid generated by rotating about the x-axis the region enclosed by the curve y=sec x and the lines x=0, y=0, and x=pi/3. Answer: pi*sqrt(3) Please show all your work. Thanks. Apr 21 | Sun from Los Angeles, CA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
Use disk method. Infinitesimally small volume of a disk is given by: dV=πr(x)^{2}dx, where r(x) is the radius of the disk, dx is its thickness. r(x)=y(x)=sec (x) Thus, V=π∫_{0}^{π/3}sec^{2}(x)dx=π(tan(π/3)-tan(0))=π√3 Apr 22 | Kirill Z. Comment