How do I find the molecular weight and the molar expression of Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O After balancing it? I've been confused about this equation.

## How do I find the molecular weight of Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O?

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# 1 Answer

The balanced equation will be= 3(Ca(OH)2) + 2(H3PO4) => Ca3(PO4)2 + 6H2O; This means that 3 Moles of Ca(OH)2 plus 2 Moles of (H3(PO4)2) Produce one Mole of Ca3(PO4)2 plus 6 Moles of water.

Molecular weights:

Ca(OH)2 = atomic weights: Ca =40; O =16; H =1. Molecular weight of compound 74 (40+(16+1)*2)

H3PO4 = atomic weights: H=1; O =16; P =31. Molecular weight of compound 98 ((3*1) +31+(16*4))

Ca3(PO4)2 = atomic weights: Ca =40; O=16; P=31. Molecular weight of compound 310 ((40*3)+(31+(16*4))*2)

H2O = atomic weights: H=1, O=16. Molecular weight: 18 ((1*2)+16)

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