9 7 __ + ___ x x to second power _________________ 5 3 _ + __ y y second power How do I solve this? Apr 7 | Dan from Saint Paul, MN | 1 Answer | 0 Votes Mark favorite Subscribe Comment
E = (9/x + 7/x^2)/(5/y + 3/y^2) Can’t divide by zero, so x≠0 and y≠0. xy≠0 includes both. Multiply right side by 1=(x^2y^2)/(x^2y^2): E = (9x^2y^2/x + 7x^2y^2/x^2) /(5x^2y^2/y + 3x^2y^2/y^2), xy≠0 E = (9xy^2 + 7y^2)/(5x^2y + 3x^2), xy≠0 E = y^2(9x+7)/(x^2(5y+3)), y≠0 [Try substituting y=0 in original and final E. The result should be the same, right?] Apr 7 | Steve S. Comment