It's a distributive problem and I don't know what to do first. Please help me

## What do I do first in this problem? 4x(6x+6)=38

# 2 Answers

**4x(6x+6)=38**

**Step 1: Distribute** 24x^{2} + 24x = 38

**Step 2: Get rid of coefficient in front of x ^{2}, so factoring is easier.**

x^{2} + x = ^{38}/_{24}

**Step 3: Reduce the fraction on the right side.**

x^{2} + x = ^{19}/_{12}

**Step 4: ****Complete the square on the left side.**

x^{2} + x + ^{1}/_{4} = ^{
19}/_{12} + ^{1}/_{4}

**Step 5: factor the equation on the left and reduce the numerical expression on the right.**

(x + ^{1}/_{2})^{2} = ^{
22}/_{12}

**Step 6: In order to solve for x, take the square root of the number on the right side. **

(x + ^{1}/_{2}) = **(plus or minus)** sqrt (^{22}/_{12})

**Step 7:** **x = ^{1}/_{6} (-3 - sqrt(66))**

** x = ^{1}/_{6} (sqrt(66) - 3)**

First you have to distribute the 6x to the 4x+4 to get.

24x^2+24x=38

Since there are no easy factors, we'll need to proceed with the completing square method.

First divide both sides by 24

x^2+x=38/24

Then complete the square on left

(x+1/2)^2 - 1/4 = 38/24

(x+1/2)^2 = 44/24

x+1/2 = +- 44/24

x = -1/2 +- 11/6

## Comments

You're correct. I forgot to type out the sqrt().

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