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what is the polynomials factor of b2 + 8b + 7?

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2 Answers

You're being asked to factor this polynomial b2 + 8b + 7 into two factors (binomials). If you "FOIL" or redistribute the two binomials, you should obtain the original polynomial.
 
With this idea, what are the factors of b2? Just b*b. So the first terms of your factors will be:
(b +  )(b +  )

You notice I filled in the +'s because the original problem had two +'s.
 
Now what are the factors of 7? Just 7*1, so now we fill that in and we are done!
(b + 7)(b + 1)
( b + m ) ( b + n) =
 
  ( b + m) b + n ( b+ m) = b^2 + mb + nb + nm = b^2  +( m+n )b + mn
 
      You m, n should be such that:
     
      m+ n = 8
      mn = 7
 
        turns out: m=7, n =1