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sin2x = tanx(2-2sin^2 x)

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1 Answer

sin2x=tanx(2-2sin^2x)
2sinxcosx=(sinx/cosx)(2-2sin^2x)   (because sin2x=2sinxcosx and tanx=sinx/cosx)
divide both sides by 2
sinxcosx=(sinx/cosx)(1-sin^2x)
sinxcosx=(sinx/cosx)(cos^2x)    (because sin^2x+cos^2x=1
sinxcosx=sinxcosx  (because cos^2x/cosx=cosx; you are simplifying)
 

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