When multiplying y ^2 by y^-2 do you add the exponents? If so that would be zero correct?

Yes, you are right, Nicholas; the rule for multiplying two exponential terms with the same base is:

y

^{a}y^{b}= y^{a+b}So, yes, you are right again:

y

^{2}y^{-2}= y^{2+(-2)}= y^{0}Now what does y

^{0}= ? (Hint: it's not zero)
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