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Factor the trinomial completely

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2 Answers

Hi Paula,
 
6p²-5p-6 = 6p²-9p+4p-6
 
              =3p(2p-3)+2(2p-3)
 
              =(3p+2)(2p-3)
 
The solutions are
3p+2=0
 
p=-2/3
 
2p-3=0
 
p=3/2
by finding D = b^2-4*a*c , you can check whether the above equation is easily factorable. 
D=169, which is a perfect square, which means a factor able equation 
Using a quadratic equation, you can easily find out p = 18/12 or p=-8/12. Therefore,  
6p^2-5p-6=(2p-3)(3p+2)

Comments

Show more of your solution process. How did you get p = 18/12 or p=-8/12? And how does that get to 6p^2-5p-6=(2p-3)(3p+2)?

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