homework help
Perimeter = 2Width + 2Length, or 208 = 2W + 2L
L = W + 30, plug into above equation --> 208 = 2W + 2(W+30)
Expand: 208 = 2W + 2W + 30
Combine like terms: 178 = 4W --> W = 44.5 in.
Solve for L: L = 44.5 + 30 --> L = 74.5 in.
homework help
Perimeter = 2Width + 2Length, or 208 = 2W + 2L
L = W + 30, plug into above equation --> 208 = 2W + 2(W+30)
Expand: 208 = 2W + 2W + 30
Combine like terms: 178 = 4W --> W = 44.5 in.
Solve for L: L = 44.5 + 30 --> L = 74.5 in.
Actually, I think Victoria's answer is incorrect.
Her method is correct, but her solution doesn't work:
Given that the perimeter is twice the length plus twice the width, and the length is 30 inches longer than the width, we can indeed make an equation as follows:
2L + 2W = 208 and since L = W + 30, 2 (W + 30) + 2W = 208
Here is the first way to do it: 2 (W + 30) = 2W + 60, so 2 (W + 30) + 2W = 4W +60
so 4W + 60 = 208 subtract 60 from each side
4W = 148 divide each side by 4
W = 37
And since L = W + 30, L = 67
And now, to check our work, 2L = 67 * 2 = 134
2W = 37 * 2 = 74
So the perimeter which is twice the length plus twice the width = 2L + 2W = 134 + 74 = 208.
Comments
Good answer Victoria, but you forgot to multiply the 30 by 2 (in the second line). Your length and width give a perimeter of 238 inches.