homework help

x + (x+2) + (x+4) = [x * (x+2)] - 36

x + x + 2 + x + 4 = [x^{2} + 2x] - 36

3x + 6 = x^{2} + 2x -36

0 = x^{2} + 2x - 3x - 36 - 6

0 = x^{2} - x - 42

0 = (x - 7)(x + 6)

x = -6 or 7

We know x = 7 because -6 is not odd

When x = 7, our consecutive integers are 7, 9 (or x+2) , and 11 (or x+4)