Search 75,897 tutors
FIND TUTORS
Ask a question
0 0

1/2 Log r + 1/3 log s - 1/4 log t

Tutors, please sign in to answer this question.

3 Answers

L = 1/2 log r + 1/3 log s - 1/4 log t
 
Use Power Rule of Logarithms:
 
L = log(r^(1/2)) + log(s^(1/3)) - log(t^(1/4))
 
Use Multiplication Rule of Logarithms:
 
L = log( (r^(1/2)) * (s^(1/3)) ) - log(t^(1/4))
 
Use Quotient Rule of Logarithms:
 
L = log( ( (r^(1/2)) * (s^(1/3)) ) / (t^(1/4)) )
The question is combine all log terms as one log
 
    We make use of properties of log function:
 
       log AB = log A + lobB
 
         A = ab      b = log aA
 
 
      1/2 log r + 1/3 logS - 1/4 log t 
 
          log (√r . 3√s) / 4√t ) = log 24√( r12 . S8/  t6 )
 
 
       Note that    a1/n n√a
 
                        n√a . m√b  = mn√ (an . bm )        
Hi Juan;
I do not know what you are trying to do.  I will do my best...
1/2 Log r + 1/3 log s - 1/4 log t
Let's apply the principle of...
log xy=y log x
log r1/2+log s1/3-log t1/4
Let's apply the principle of...
log ab=log a + log b
log (r1/2)(s1/3)-log t1/4
Let's apply the principle of...
log a/b=log a - log b
log[(r1/2)(s1/3)]/(t1/4)