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(5a)x-17^2+14a

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Vivian is right, Zaire, the equation you provided is not a quadratic since there is no x2 term.  Also, I assume a is a constant?  Did you mean f(x) = 5ax - 17x2 + 14a, or f(x) = 5ax - 172 + 14a.  Also are you solving for the case where f(x) = 0?  Please clarify and we'll help.